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| BODMAS RULE PART 3 |
Frequently Asked Questions related to BODMAS Rule
1) 40 + 15 x 4
Ans. Multiplication before Addition
First 15 x 4 = 60 , then 40 + 60 = 100 2) ( 350 + 400 ) x 2
Ans. Brackets First and then Addition
i.e. 350 + 400 = 750 , then 750 x 2 = 1500
3) 25 + 33 ÷ 11 x (27 ÷ 9)2 - 12
Ans. According to BODMAS Rule first we are going to solve Brackets
Thus we divide 27 by 9 and arrive at 3
i.e. 25 + 33 ÷ 11 x (3)2 -12
Next we are going to evaluate Order (power) - Thus we solve (3)2 and get 9
Therefore 25 + 33 ÷ 11 x 9 - 12
Now we divide 33 by 11 and get 3
Thus 25 + 3 x 9 - 12
Than we multiply 3 by 9 and we get 27 So 25 + 27 - 12
Finally We add 25 and 27 and get 52 and We deduct 12 from 52 and get 40
Hence 25 + 33 ÷ 11 x (27 ÷ 9)2 - 12 = 40
4) 7 + (6 × 52 + 3)
Ans. 7 + (6 × 25 + 3) [Start inside Brackets, and then use "Orders" First i.e. Power ]
7 + (150 + 3) [Then Multiply]
7 + (153) [Now Add]
7 + 153 [Brackets completed, last operation is add]
160 [DONE]
5) 2*6+3-4/2-5+20/5*3+50
Ans. 12+3-4/2-5+20/5*3+50
= 12+3-2-5+20/5*3+50
= 12+3-2-5+4*3+50
= 12+3-2-5+12+50
= 15-2-5+12+50
= 13-5+12+50
= 8+12+50
= 20+50
= 70
6) 9*9-30/3+5-6+7-2+9*9
Ans. 81-30/3+5-6+7-2+9*9
= 81-10+5-6+7-2+9*9
= 81-10+5-6+7-2+81
= 71+5-6+7-2+81
= 76-6+7-2+81
= 70+7-2+81
= 77-2+81
= 75+81
= 156
7) 10*10/2+60-30/3*(20-36/(2+8*2)/2)/4
Ans. 10*10/2+60-30/3*(20-36/(2+16)/2)/4
= 10*10/2+60-30/3*(20-36/18/2)/4
= 10*10/2+60-30/3*(20-2/2)/4
= 10*10/2+60-30/3*(20-1)/4
= 10*10/2+60-30/3*19/4
= 100/2+60-30/3*19/4
= 50+60-30/3*19/4
= 50+60-10*19/4
= 50+60-190/4
= 50+60-47.5
= 110-47.5
= 62.5
8) ((90+4)/2-6*7/2+((7+4)*10)+8*9-5)*10+8
Ans. (94/2-6*7/2+((7+4)*10)+8*9-5)*10+8
= (94/2-6*7/2+(11*10)+8*9-5)*10+8
= (94/2-6*7/2+110+8*9-5)*10+8
= (47-6*7/2+110+8*9-5)*10+8
= (47-42/2+110+8*9-5)*10+8
= (47-21+110+8*9-5)*10+8
= (47-21+110+72-5)*10+8
= (26+110+72-5)*10+8
= (136+72-5)*10+8
= (208-5)*10+8
= 203*10+8
= 2030+8
= 2038
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